# 原题

编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

 

示例 1:

输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:

输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]

# 解 :

# 1、暴力破解

var reverseString = function (s) {
    return s.reverse()
};

# 2、双指针

var reverseString = function (s) {
    for (let i = 0; i < (s.length - 1) / 2; i++) {
        let temp = s[s.length - i - 1]
        s[s.length - 1 - i] = s[i]
        s[i] = temp
    }
    return s
};
Last Updated: 4/3/2020, 6:21:54 PM